My Take on Layers

Dear Maglie et al.

            I will have to confess I have thought of a way to do layers. Let’s assume that there is a four-dimensional cover on a five-dimensional ball. We have used w, x, y, and z so let’s add v. The equation for the cover is:


However, if v is a constant for every layer so that each layer is created:


x=bθ cosθ

y=bθ sinθ cosφ

z=bθ sinθ sinφ cosξ

w=bθ sinθ sinφ sin ξ

r=Rmax²-v² =time/distance, where v is a constant, in each 3-d spiral. 

            One would assume that would be equal to zero in the Space Angel’s layer and something larger for our layer and even larger for the inner layers. It would still be part of the cover to a ball rather than a tube. Layers could be as close as seemed necessary for the empirical data. I can’t visualize it in my head, but I bet Lemma can if he lives in 6-d. Of course we still must explain the difference in the speed of light. 

            How is that?



Leave a Reply

Fill in your details below or click an icon to log in: Logo

You are commenting using your account. Log Out /  Change )

Twitter picture

You are commenting using your Twitter account. Log Out /  Change )

Facebook photo

You are commenting using your Facebook account. Log Out /  Change )

Connecting to %s